We can solve this equation using only algebra. Isolate the expression tanx on the left side of the equals sign. 2(tanx) + 2(3) = 5 + tanx 2tanx + 6 = 5 + tanx 2tanx − tanx = 5 − 6 tanx = − 1. There are two angles on the unit circle that have a tangent value of − 1: θ = 3π 4 and θ = 7π 4.
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We can solve this equation using only algebra. Isolate the expression tanx on the left side of the equals sign. 2(tanx) + 2(3) = 5 + tanx 2tanx + 6 = 5 + tanx 2tanx − tanx = 5 − 6 tanx = − 1. There are two angles on the unit circle that have a tangent value of − 1: θ = 3π 4 and θ = 7π 4.