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Case Study Questions Class 10 Science Light Reflection and Refraction

Case study questions class 10 science chapter 10 light reflection and refraction, case study:1.

If less is the refractive index then less will be the bending or medium is rarer and velocity of light will be more in that medium. Like the refractive index of air is found to be 1.0003 and that of water is found to be 1.33. And hence water is more denser than air, air is rarer medium as compared to water. Thus, velocity of light in air medium is greater than velocity of light in water medium.

Absolute Refractive index= (speed of light in air)/(speed of light in medium) = c/v

2) How you can define rarer and denser medium on the basis of optical density?

Case study: 2

1/v + 1/u = 1/f

Similarly in case of lenses, lens formula is given by

1/v – 1/u = 1/f

Thus, P = 1/f

2) What is the sign of power of convex and concave lens?

P= P1 + P2 + P3 + P4

4) If the magnification produced is negative then the image formed is real. And if the magnification produced is positive then the image formed is virtual.

Case study:3

3) Concave mirror is called as converging mirror while convex mirror is called as diverging mirror.

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CBSE 10th Standard Science Subject Light Reflection and Refraction Chapter Case Study Questions With Solution 2021

By QB365 on 21 May, 2021

QB365 Provides the updated CASE Study Questions for Class 10 , and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get  more marks in Exams 

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Cbse 10th standard science subject light reflection and refraction case study questions with solution 2021.

10th Standard CBSE

Final Semester - June 2015

The curved surface of a spoon can be considered as a spherical mirror. A highly smooth polished surface is called mirror. The mirror whose reflecting surface is curved inwards or outwards is called a spherical mirror. Inner part works as a concave mirror and the outer bulging part acts as a convex mirror. The center of the reflecting surface of a mirror is called pole and the radius of the sphere of which the mirror is formed is called radius of curvature. (i) When a concave mirror is held towards the sun and its sharp image is formed on a piece of carbon paper for some time, a hole is burnt in the carbon paper. What is the name given to the distance between the mirror and carbon paper?

(ii) The distance between pole and focal point of a spherical mirror is equal to the distance between

(iii) The focal length of a mirror is 15 cm. The radius of curvature is

(iv) The normal at any point on the mirror passes through

(v) In a convex spherical mirror, reflection of light takes place at

The spherical mirror forms different types of images when the object is placed at different locations. When the image is formed on screen, the image is real and when the image does not form on screen, the image is virtual. When the two reflected rays meet actually, the image is real and when they appear to meet, the image is virtual. A concave mirror always forms a real and inverted image for different positions of the object. But if the object is placed between the focus and pole, the image formed is virtual and erect. A convex mirror always forms a virtual, erect and diminished image. A concave mirror is used as doctor's head mirror to focus light on body parts like eyes, ears, nose etc., to be examined because it can form erect and magnified image of the object. The convex mirror is used as a rear view mirrors in automobiles because it can form an small and erect image of an object. (i) When an object is placed at the centre of curvature of a concave mirror, the image formed is

(ii) No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be

(iii) A child is standing in front of a magic mirror. She finds the image of her head bigger, the middle portion of her body of the same size and that of the legs smaller. The following is the order of combinations for the magic mirror from the top.

(iv) To get an image larger than the object, one can use (a) convex mirror but not a concave mirror (b) a concave mirror but not a convex mirror (c) either a convex mirror or a concave mirror (d) a plane mirror. (v) A convex mirror has wider field of view because (a) the image formed is much smaller than the object and large number of images can be seen (b) the image formed is much closer to the mirror (c) both (a) and (b) (d) none of these.

The relation between distance of an object from the mirror (u), distance of image from the mirror (v) and the focal length (F) is called mirror formula. This formula is valid in all situations for all spherical mirrors for all positions of the object. The size of image formed by a spherical mirror depends on the position of the object from the mirror. The image formed by a spherical mirror can be bigger than the object, equal to the object or smaller than the object. The size of the image relative to the object is given by the linear magnification (m). Thus, the magnification is given by the ratio of height of image to the height of object. If magnification is negative, image is real and if it is positive, image is virtual. (i) What is the position of an image when an object is placed at a distance of 20 em from a concave mirror of focal length 20 cm?

(iii) If the magnification of an image is -2, the characteristic of image will be

(iv) The mirror formula holds for

(v) A parallel beam of light is made to fall on a concave mirror. An image is formed at a distance of7.5 from the mirror. The focal length of the mirror is

(ii) A ray of light passes from a medium A to another medium B. No bending of light occurs if the ray of light hits the boundary of medium B at an angle of

(iii) When light passes from one medium to another, the frequency of light

(iv) When light passes from glass to water, the speed of light

(v) The bottom of pool filled with water appears to be ______ due to refraction of light

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Cbse 10th standard science subject light reflection and refraction case study questions with solution 2021 answer keys.

(i) (d) : When an object is placed at the focus of a concave mirror, the..image is formed at infinity. (ii) (d) : When a light ray parallel to the principal axis is incident on a concave mirror, it passes through the principal focus after reflection. Therefore, figure D is correct. (iii) (a) : If m is negative, the image will be real and inverted. (iv) (d) (v) (b): The distance of object from mirror =  \(\infty\) Using,  \(\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\) \(\frac{1}{\infty}-\left(-\frac{1}{7.5}\right)=\frac{1}{f}\) f = 7.5 cm

(i) (a): When, a ray of light travels from air to glass, it bends towards the normal. (ii) (c): No bending of light occurs when light is incident normally or perpendicularly on a boundary of two media since angle of incidence and angle of refraction both are zero. (iii) (c): When light goes from one medium to other medium, its frequency does not change (iv) (a): The speed to light increases when light passes from glass to water as water is optically rarer medium. (v) (a): The bottom of a pool of water appears to be less deep than it actually is due to refraction.

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Case Study Chapter 10 Light Reflection and Refraction

Please refer to Chapter 1 Light Reflection and Refraction Case Study Questions with answers provided below. We have provided Case Study Questions for Class 10 Science for all chapters as per CBSE, NCERT and KVS examination guidelines. These case based questions are expected to come in your exams this year. Please practise these case study based Class 10 Science Questions and answers to get more marks in examinations.

Case Study Questions Chapter 1 Light Reflection and Refraction

Case/Passage – 1 A 5.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm.

Question: What is the power of the used lens? (a) + 5 D (b) – 5 D (c) + 0.5 D (d) – 0.5 D   

Question: What is the distance of image from the pole of lens? (a) v = 60 cm (b) v = – 60 cm (c) v = 30 cm (d) v = –30 cm 

Case/Passage – 2

Light travels through a vacuum at a speed c = 3 × 108 m/s. It can also travel through many materials, such as air, water and glass. Atoms in the material absorb, reemit and scatter the  light, however. Therefore, light travels through the material at a speed that is less than c, the actual speed depending on the nature of the material. To describe the extent to which  the speed of light in a material medium differs from that in a vacuum, we use a parameter called the index of refraction (or refractive index).

Question: Figure shows a ray of light as it travels from medium A to 

medium B. Retractive index of the medium B relative to medium A is (a) √3/2 (b)√2/3 (c)√1/2 (d) √2

Question:The path of a ray of light coming from air passing through a rectangular glass slab traced by four students shown as A, B, C and D in the figure. Which one of them is correct?

(a) A (b) B (c) C (d) D   

Question: A light ray enters from medium A to medium B as shown  

in the figure. The refractive index of medium B relative to A will be  (a) greater than unity (b) less than unity (c) equal to unity (d) zero

Question: You are given water, mustard oil, glycerine and kerosene.  In which of these media, a ray of light incident obliquely at same angle would bend the most? (a) Kerosene (b) Water (c) Mustard oil (d) Glycerine   

Question: A ray of light is incident in medium 1 on a surface that separates medium 1 from medium 2. Let v1 and v2 represent the velocity of light in medium 1 and medium 2 respectively. Also let n12 and n21 represent the refractive index of medium 1 with respect to medium 2 and refractive index of medium 2 with respect to medium 1, respectively. If i and r denote the angle of incidence and angle of refraction, then- (a) sin i/sin r = n 21 V 1 /V 2 (b) sin i/sin r = n 21 V 2 /V 1 (c) sin i/sin r = n 12 V 1 /V 2 (d) sin i/sin r = n 12  V 2 /V 1   

Case/Passage – 3 Inside a substance such as glass or water, light travels more slowly than it does in a vacuum. If c denotes the speed of light in a vacuum and v denotes its speed through some other substance, then v = c/n where n is a constant called the index of refraction. To good approximation, a substance’s index of refraction does not depend on the wavelength of light. For instance, when red and blue light waves enter water, they both slow down by about the same amount. More precise measurements, however, reveal that n varies with wavelength. Table presents some indices of refraction of Custon glass, for different wavelengths of visible light. A nanometer (nm) is 10– 9  meters. In a vacuum, light travels as c = 3.0 × 10 8  m/s 

Question: Inside Custon glass (a) Orange light travels faster than yellow light (b) Yellow light travels faster than orange light (c) Orange and Yellow light travels equally fast (d) We cannot determine which color of light travels faster 

Question: Which of the following phenomena happens because n varies with wavelength (a) A lens focuses light (b) A prism breaks sunlight into different colors (c) Total internal reflections ensures that light travels down a fiber optic cable (d) Light rays entering a pond change direction at the pond’s surface 

Question: For blue-green of wavelength 520 nm, the index of refraction of Custon glass is probably closest to (a) 1.49 (b) 1.50 (c) 1.51 (d) 1.52 

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Case Study Questions Class 10 Science Chapter 10 Light Reflection and Refraction

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CBSE Board Exam is on the way, so you must practice some good Case Study Questions Class 10 Science to boost your preparation to score 95+% on Boards. In this post, you will get Case Study and Passage Based Questions that will come in CBSE Class 10 Science Board Exams .

Join our Telegram Channel, there you will get various e-books for CBSE 2024 Boards exams for Class 9th, 10th, 11th, and 12th.

In CBSE Class 10 Science Paper, Students will have to answer some questions based on  Assertion and Re a son . There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Light Reflection and Refraction Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 10 Science  Chapter 10 Light Reflection and Refraction

Case Study/Passage-Based Questions

Question 1:

The spherical mirror forms different types of images when the object is placed at different locations. When the image is formed on the screen, the image is real and when the image does not form on-screen, the image is virtual. When the two reflected rays meet actually, the image is real and when they appear to meet, the image is virtual. A concave mirror always forms a real and inverted image for different positions of the object. But if the object is placed between the focus and pole, the image formed is virtual and erect. A convex mirror always forms a virtual, erect, and diminished image. A concave mirror is used as a doctor’s head mirror to focus light on body parts like eyes, ears, nose, etc., to be examined because it can form erect and magnified images of the object. The convex mirror is used as a rear view mirror in automobiles because it can form a small and erect image of an object.

(i) When an object is placed at the center of curvature of a concave mirror, the image formed is

Answer: (c) same size as that of the object

(ii) No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be

Answer: (d): The image is erect in a plane mirror and also in a convex mirror, for all positions of the object.

(iii) A child is standing in front of a magic mirror. She finds the image of her head bigger, the middle portion of her body of the same size and that of the legs smaller. The following is the order of combinations for the magic mirror from the top.

Answer: (c) : As the image of head is bigger, the upper portion of magic mirror is concave. The middle portion of the image is of same size, so, middle portion of magic mirror is plane. Now, the image of legs looks smaller, therefore, the lower portion of magic mirror is convex.

(iv) To get an image larger than the object, one can use (a) convex mirror but not a concave mirror (b) a concave mirror but not a convex mirror (c) either a convex mirror or a concave mirror (d) a plane mirror.

Answer: (b) a concave mirror but not a convex mirror

(v) A convex mirror has wider field of view because (a) the image formed is much smaller than the object and large number of images can be seen (b) the image formed is much closer to the mirror (c) both (a) and (b) (d) none of these.

Answer: (c) both (a) and (b)

Question 2:

The lenses form different types of images when objects are placed at different locations. When a ray is incident parallel to the principal axis, then after refraction, it passes through the focus or appears to come from the focus.

When a ray goes through the optical center of the lens, it passes without any deviation. If the object is placed between the focus and the optical center of the convex lens, an erect and magnified image is formed.

As the object is brought closer to the convex lens from infinity to focus, the image moves away from the convex lens from focus to infinity. Also, the size of the image goes on increasing and the image is always real and inverted.

A concave lens always gives a virtual, erect, and diminished image irrespective of the position of the object.

(i) The location of image formed by a convex lens when the object is placed at infinity is (a) at focus (b) at 2F (c) at optical center (d) between Fand 2F

Answer: (a) at focus

(ii) When the object is placed at the focus of concave lens, the image formed is (a) real and smaller (b) virtual and inverted (c) virtual and smaller (d) real and erect

Answer: (b) virtual and inverted

(iii) The size of image formed by a convex lens when the object is placed at the focus of convex lens is (a) small (b) point in size (c) highly magnified (d) same as that of object

Answer: (c) highly magnified

(iv) When the object is placed at 2F in front of convex lens, the location of image is (a) at F (b) at 2 F on the other side (c) at infinity (d) between F and optical center

Answer: (b) at 2 F on the other side

(v) At which location of object in front of concave lens, the image between focus and optical centre is formed (a) anywhere between centre and infinity (b) at F (c) at 2F (d) infinity

Answer: (a) anywhere between centre and infinity

Case Study 3: Light reflection and refraction are fundamental phenomena that occur when light interacts with surfaces and passes through different mediums. Reflection is the bouncing back of light when it strikes a surface. The laws of reflection state that the angle of incidence is equal to the angle of reflection, and the incident ray, reflected ray, and normal at the point of incidence lie in the same plane. Refraction, on the other hand, is the bending of light as it passes from one medium to another with a different optical density. The bending of light is governed by Snell’s law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant for a given pair of media. The concepts of reflection and refraction help us understand various optical phenomena, such as the formation of images by mirrors and lenses, the dispersion of light, and the phenomenon of total internal reflection.

What is reflection? a) The bending of light as it passes from one medium to another b) The bouncing back of light when it strikes a surface c) The formation of images by mirrors and lenses d) The dispersion of light Answer: b) The bouncing back of light when it strikes a surface

What do the laws of reflection state? a) The angle of incidence is equal to the angle of reflection b) The incident ray, reflected ray, and normal lie in the same plane c) The angle of incidence, angle of reflection, and normal form a right triangle d) All of the above Answer: d) All of the above

What is refraction? a) The bending of light as it passes from one medium to another b) The bouncing back of light when it strikes a surface c) The formation of images by mirrors and lenses d) The dispersion of light Answer: a) The bending of light as it passes from one medium to another

What law governs the bending of light during refraction? a) Law of reflection b) Snell’s law c) Newton’s law d) Coulomb’s law Answer: b) Snell’s law

What optical phenomena can be explained using the concepts of reflection and refraction? a) Formation of images by mirrors and lenses b) Dispersion of light c) Total internal reflection d) All of the above Answer: d) All of the above

Hope the information shed above regarding Case Study and Passage Based Questions for Class 10 Science Chapter 10 Light Reflection and Refraction with Answers Pdf free download has been useful to an extent. If you have any other queries about CBSE Class 10 Science Light Reflection and Refraction Case Study and Passage Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible. By Team Study Rate

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Class 10 Science Chapter 9 Case Based Questions - Light Reflection and Refraction

Correct Answer is Option (b) In rectangular glass slab the ray undergoes only refraction and emerges out parallel. In a prism the emerging ray is not parallel but split due to change in wavelength of different colour of light. The shape of the glass slab with two prisms up and down splits light but recombines it into one.

Question 2: The light changes its path as its medium changes. Which of the following is incorrect statement. (a)  Speed of light is different in different media. (b)  Light changes its path because light only travels in straight line. (c) Speed of light is dependent on medium through which it is passing. (d)  The light chooses the path with minimum time, as it changes its medium.

Correct Answer is Option (b) Light changes its path because light only travels in straight line.

Question 3: Light travel fastest in: (a)  Air (b)  Vacuum (c)  Glass (d) diamond

Correct Answer is Option (b) Light travels faster in vacuum than any other medium. This is because there is no obstruction in vacuum for the propagation of light and thus, the refractive index of vacuum is the lowest.

An object is kept at a distance of 18 cm, 20 cm, 22 cm and 30 cm, from a lens of power + 5D. Question 4:  The focal length of the given lens is: (a) 0.2 cm (b) 20 cm (c) 5cm (d) 0.5 cm

Correct Answer is Option (b) P = 1/f, f = 100/5 = 20 cm

Question 5: In which case or cases would you get a magnified image? (a)  18cm (b)  20cm (c)  22cm (d)  All the above

Correct Answer is Option (d) An object at 18 cm, 22 cm, and 30 cm, the image can be magnified.

Question 6: The power of a lens of focal length 1 metre is called as: (a)  Refractive index (b) 1 dioptre (c)  Speed of light (d)  Wavelength

Correct Answer is Option (b) The power of a lens whose focal length is one metre is dioptre .

Question 7: Name the lens/mirror used in film projectors and telescopes: (a)  Convex lens (b) Concave lens (c)  Convex mirror (d)  Concave mirror

Correct Answer is Option (a) Convex lens used in film projectors and telescopes, where the distance between the eye's lens and retina is too short, as a result of which the focal point lies behind the retina. Eyeglasses with convex lenses increase refraction, and accordingly reduce the focal length.

Question 8: Which of the magnified image can we get on a screen? (a) At 18 cm (b)  At 18 cm and 22 cm (c)  At 20 cm and 22 cm (d)  At 22 and 30 cm

Correct Answer is Option (d) At 22 cm and 30 cm, image can be obtained on a screen.

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Question 3 - Case Based Questions (MCQ) - Chapter 10 Class 10 - Light - Reflection and Refraction

Last updated at April 16, 2024 by Teachoo

A student wants to project the image of a candle  flame on a screen 60 cm in front of a mirror by  keeping the flame at a distance of 15 cm from its  pole.  

(a) suggest the type of mirror he should use:  , (i) convex mirror , (ii) plane mirror  , (iii) concave mirror , (iv) none of the above  .

Since the student wants image on a screen , it has to be a real image

Now, let’s check both mirrors

• Convex mirrors always produce virtual images . It cannot be used to produce images on the screen.
• Concave mirrors produce real images on the screen in all cases except when the object is between pole and focus , therefore students should use a concave mirror because it forms real images.
• Plane mirrors always form virtual images. So, it cannot be used

So, the correct answer is (iii) Concave mirror  

(b) Find the linear magnification of the image  produced.  

(i) – 4 , (ii) + 4  , (iii) – 900 , (iv) + 900  .

So, the correct answer is (i) – 4 

(c) When object distance is less than focal length the image is _______ and when object distance is more  than focal length the image is  ______.  

(i) real, real , (ii) virtual. virtual  , (iii) real, virtual , (iv) virtual, real.

In a concave mirror

• When object is kept between Focus and Pole , image formed is virtual
• When object is kept beyond focus (between C and F, at C and beyond C), image formed is real 

So, the correct answer is (iv) virtual, real 

(d) Draw  a ray diagram for the given scenario. 

(e) What is the distance between the object and its image?  

(i) 15 cm , (ii) 45 cm  , (iii) 75 cm , (iv) 0 cm  .

Object distance, u = -15cm

Image distance, v = -60cm

Distance between object and image = u - v 

= -15 - (-60)

The correct answer is (ii) 15 cm 

(e) The image formed in the above case is:  

(i) virtual, inverted and magnified.  , (ii) real, erect and magnified  , (iii) real, inverted and magnified  , (iv) real, erect and diminished  .

Ans.    

• Since the image is formed on a screen , it is real .

Also, we calculated the magnification of the image as m= -4. 

• Since M = image size/object size, it is clear that the image is 4 times larger than the object. 
• Hence it is magnified. 
• The negative sign in the magnification means that the image is inverted.  

Thus, the correct answer is (i) real, inverted and magnified

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CBSE Class 10 Important Questions on Science Chapter 10 - Light Reflection and Refraction 2024-25

• Class 10 Important Question
• Chapter 10: Light Reflection And Refraction

CBSE Class 10 Science Chapter-10 Important Questions with Answers - Free PDF Download

The concept of light, reflection, and refraction is quite fascinating for the students of Class 10. In the previous classes, students have learned a lot of new things related to these two natural phenomena occurring with light. In Class 10, they will advance to a new level of concepts related to reflection and refraction. The textbook explains the concepts pretty well. Students will need more Light Reflection and Refraction Class 10 Important Questions with answers to prepare for the exams.

By studying the Class 10 Science Chapter 10 Important Questions, you will develop your concept for this chapter in a better way. In fact, your answering skills will also increase considerably. Check out how the expert teachers at Vedantu have answered the Light Class 10 Important Questions niftily. Download the PDF and follow the format of answering questions as shown by the experts to score more. Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. Maths Students who are looking for the better solutions, they can download Class 10 Maths NCERT Solutions to help you to revise complete syllabus and score more marks in your examinations.

Download CBSE Class 10 Science Important Questions 2024-25 PDF

Also, check CBSE Class 10 Science Important Questions for other chapters:

Related Chapters

Important Topics under CBSE Class 10 Science Chapter 10 - Light Reflection and Refraction

The following list of important topics covered under the chapter on Light Reflection and Refraction has been provided for students so that they can take a glance at the major concepts and read them through before diving into the important questions.

Reflection of Light

Spherical Mirrors

Image Formation by Spherical Mirrors

Sign Convention for Spherical Mirrors

Mirror Formula and Magnification

Refraction of Light

Refraction through a Rectangular Glass Slab

Refractive Index

Refraction by Spherical Lenses

Image Formation by Lenses and Their Ray Diagrams

Sign Convention for Spherical Lenses

Lens Formula and Magnification

Power of a Lens

Study Important Questions for Class 10 Science Chapter 10 - Light Reflection and Refraction

Long Answer Questions (5 Marks)

1. A convex lens has a focal length of \[10\] cm. At what distance from the lens should the object be placed so that it forms a real and inverted image $20$ cm. away from the lens? What would be the size of the image formed if the object is $2$ cm high? With the help of a ray, the diagram shows the formation of the image by the lens in this case?

Ans: Given, the focal length of the convex lens,

$\Rightarrow f=+10$ cm

Also, given the image formed is real and inverted with the image distance as $20$ cm.

$\Rightarrow v=+20$ cm

From the lens formula, we have: 

$\Rightarrow \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\Rightarrow \dfrac{1}{10}=\dfrac{1}{20}-\dfrac{1}{u}$

$\Rightarrow \dfrac{1}{u}=\dfrac{1}{20}-\dfrac{1}{10}$

$\Rightarrow \dfrac{1}{u}=\dfrac{-1}{20}$

$\Rightarrow u=-20$ cm.

$\therefore $ The object is placed at a distance of $20$ cm.

Magnification is given as,

$\Rightarrow m=-\dfrac{v}{u}$

$\Rightarrow m=-\dfrac{20}{\left( -20 \right)}$

$\Rightarrow m=+1$

Also, magnification is given by, $m=\dfrac{Height\text{ of the image}}{Height\text{ of the object}}$.

$\therefore m=\dfrac{Height\text{ of the image}}{2}$

$\Rightarrow 1=\dfrac{Height\text{ of the image}}{2}$

$\Rightarrow Height\text{ of the image}=2$ cm.

Thus, the image is of the same size as that of the object and it is real and inverted.

The ray diagram representing the formation of the image by the lens in this case is:

It is observed that the image is formed at $2{F_2}$ with the object placed at $2{F_1}$.

2. Draw a ray diagram to show the use of a convex lens for the formation of images having the following characteristics. 

a. Real & inverted and diminished 

Ans: A ray diagram representing a real & inverted and diminished image is given below.

b. Virtual, erect & magnified.

Ans: A ray diagram representing a virtual, erect, and magnified image is given below.

3. A convex lens forms a real and inverted image of a needle at a distance of $50$ cm. from it. Where is the needle placed in front of the convex lens if the image is equal to the size of objects? Also, find the power of the lens.

Ans: Given, the image is real and inverted at a distance of $50$ cm.

$\Rightarrow v=+50$ cm

Also given, Height of image $=$ Height of object

We know, magnification is given as,

$\therefore -\dfrac{v}{u}=\dfrac{Height\text{ of the image}}{Height\text{ of the object}}$

Since, Height of image $=$ Height of object and $v=+50$ cm

$\Rightarrow -\dfrac{50}{u}=1$

$\Rightarrow u=-50$ cm

$\Rightarrow \dfrac{1}{f}=\dfrac{1}{50}-\dfrac{1}{-50}$

$\Rightarrow f=25$ cm

$\Rightarrow f=0.25$ m

The power of a lens is given by,

$\Rightarrow P=\dfrac{1}{f}$

$\Rightarrow P=\dfrac{1}{0.25}$  m

$\Rightarrow P=+4$ D

4. One-half of a convex lens is covered with black paper. Will this lens produce a complete image of the object? Verify your answers experimentally. Explain your observations.

Ans: If we cover one-half of a convex lens with black paper it is observed that it produces a complete image of the object.

Representing the given situation with a ray diagram.

Adjust the position of the burning candle such that its image is formed on the screen placed on the other side of the lens.

We get a full image of the burning candle on the screen.

Thus, from the above observation, we conclude that the formation of an image does not depend on the length of the lens, but the brightness of the image formed on the screen depends since the number of rays passing through the lens gets reduced on covering half the lens with black paper.

5. An object $5$ cm in length is held $25$ cm away from a converging lens of focal length $10$ cm. Draw the ray diagram and find the position, size, and nature of the image formed.

Ans: Given focal length of the lens, $f=+10$ cm.

Object distance from the converging lens is given to be $25$ cm and the height of the object ($ho$) is given to be $5$ cm.

$\Rightarrow u=-25$ cm

$\Rightarrow ho=5$ cm

$\Rightarrow \dfrac{1}{10}=\dfrac{1}{v}-\dfrac{1}{-25}$

$\Rightarrow \dfrac{1}{v}=\dfrac{1}{25}-\dfrac{1}{10}$

$\Rightarrow v=\dfrac{50}{3}$ cm

$\Rightarrow v=16.7$ cm

Thus, we conclude that the image formed is real and inverted and is formed at a distance of $16.7$ cm on the other side of the lens.

Also, magnification is given by, $m=\dfrac{Height\text{ of the image}}{Height\text{ of the object}}=\dfrac{hi}{ho}$.

$\therefore -\dfrac{v}{u}=\dfrac{hi}{ho}$

$\Rightarrow \dfrac{16.7}{-25}=\dfrac{hi}{5}$

$\Rightarrow hi=-\dfrac{10}{3}$ cm

Hence, the image is diminished.

The ray diagram representing the above situation is drawn below.

6. A convex lens of focal length $15$ cm formed an image $10$ cm from the lens. How far is the object placed from the lens? Draw the ray diagram.

Ans: Given focal length of the lens, $f=15$ cm.

Image distance from the converging lens is given to be $10$ cm.

$\Rightarrow v=-10$ cm

We observe that the image distance is less than the focal length, hence the image formed would be virtual and erect.

$\Rightarrow \dfrac{1}{15}=\dfrac{1}{-10}-\dfrac{1}{u}$

$\Rightarrow \dfrac{1}{u}=-\dfrac{1}{10}-\dfrac{1}{15}$

$\Rightarrow u=-6$ cm

Light: Reflection and Refraction - Important Questions and Solutions Summary

light rays, mirrors, lenses, prisms, etc., is the advanced version of what you As mentioned earlier, the chapter related to light, reflection, and refraction of have studied in the previous classes. In Class 10, you will have to focus on the theoretical part, as well as, the use of these theories to answer questions.

After you have completed answering the basic questions in the exercise, you might need a question bank to learn more about this chapter. This is where Light Reflection and Refraction Class 10 Important Questions with Answers can be used perfectly. These questions will intellectually challenge your knowledge and foundation of concepts based on this topic. You can answer on your own and check whether you know the right answer or not.

Class 10 Light Reflection and Refraction Important Questions have been developed by the expert teachers to provide a strong idea of how questions are set in the exams. All these questions are developed to define how theoretical concepts are used to solve conceptual problems. You will gain a better insight into the chapters and strengthen your foundation accordingly.

Benefits of Studying the CBSE Class 10 Important Questions on Science Chapter 10 - Light Reflection and Refraction

The Important Questions for Class 10 Light Reflection and Refraction have been developed based on the basic and advanced concepts you have learned in your science textbook. Let us check the benefits of studying these questions first.

Thinking Out of the Box

The Important Questions of Light Reflection and Refraction Class 10 is the ultimate suggestion for the upcoming board exam. You can study these questions, prepare their answers on your own, and compare them with the solution provided. This will help you to understand how efficiently you have studied the chapter. Light Class 10 Important Questions have been developed to help you think out of the box. In most cases, the thoughts of the students remain stuck in the exercises of the textbook. These questions will help them think out of the box and challenge their intellect.

Getting to Know Possible Important Questions of Chapter 10 Class 10 Science

By studying Class 10th Science Chapter 10 Important Questions , you will get to know possible questions that might come in the board exams. All these questions are developed by experienced science teachers. They are well-aware of the type of questions asked in the CBSE exam . Hence, studying these questions will help you learn about different modes and patterns.

Making Concepts Easier to Understand

The Important Questions for Class 10 Science Light Reflection and Refraction have simple explanations. All the concepts in this chapter will be exceptionally simplified and utilized to answer these important questions. Hence, the students will get another way to learn how to use the textbook concepts to solve challenging questions in the exams.

Efficient Answering Methods

The Ch 10 Science Class 10 Important Questions will also come with a proper solution. The solutions will have the perfect answers to all these important questions. You will get another set of questions and answers to follow and find out the best approaches to score well in the exams. These approaches are simplified and designed by following the CBSE guidelines .

Mastering Solving Numerical Questions

This chapter poses a challenge in the form of numerical questions related to mirrors and lenses. These problems are based on a set of formulas related to the focal distance, object distance, and image distance of lenses and mirrors. By using Class 10 Science Chapter 10 Important Questions and Solutions, you can master using the formula in different aspects without committing mistakes.

You can download Chapter 10 Science Class 10 Important Questions and solutions in PDF format and study them offline. Get this extra set of questions and use them as a reference to clear your concepts of this crucial chapter.

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FAQs on CBSE Class 10 Important Questions on Science Chapter 10 - Light Reflection and Refraction 2024-25

1. Why Should You Prefer Vedantu for Important Questions of Light Class 10?

The teachers of Vedantu have formulated the best possible questions of Class 10 Light for the students to follow. The answers are simple and follow the CBSE guidelines. You can rest be assured that you will get the best-quality questions and answers to study.

2. Why Should You Study Light Reflection and Refraction Important Questions?

By studying the Light Reflection and Refraction Class 10 Important Questions, you will get a good idea of what questions are asked in the board exam. Follow the answering style and score more in the main exam.

3. What are the important topics covered in the CBSE Class 10 Science Chapter 10 - Light Reflection and Refraction?

The following are the important topics covered in the Chapter on Light Reflection and Refraction: 

CBSE Class 10 Science Important Questions

Cbse study materials.

• NCERT Solutions
• NCERT Solutions for Class 10
• NCERT Class 10 Science
• Chapter 10 Light Reflection And Refraction

NCERT Solutions for Class 10 Science Chapter 10: Light Reflection and Refraction

Ncert solutions class 10 science chapter 10 – cbse free pdf download.

* According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 9.

NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction is structured in a way to present a comprehensible coverage of scientific topics related to our daily life. Basic science has been laid out to students with no sharp divisions in disciplines such as Physics, Chemistry and Biology. NCERT is accepted and recommended throughout schools in the nation. Following are a few reasons to rely on NCERT Solutions :

• The tricky questions inserted between chapters force students to think out of the box and apply the concepts learned in the chapter.
• NCERT Solutions provide you with detailed solutions to the chapter questions that help you fetch marks in the CBSE exams.

Download Exclusively Curated Chapter Notes for Class 10 Science Chapter – 10 Light Reflection and Refraction

Download most important questions for class 10 science chapter – 10 light reflection and refraction.

NCERT Solutions are popular among students, especially for Science and Mathematics. NCERT Solutions for Class 10 Science Chapter 10 – Light Reflection and Refraction provided here consists of well-explained solutions to all the questions asked in the textbook. Get your hands on the comprehensive NCERT Solutions for Chapter 10 Light Reflection and Refraction, here, for free!

• Chapter 1 Chemical Reactions and Equations
• Chapter 2 Acids, Bases and Salts
• Chapter 3 Metals and Non-metals
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• Chapter 6 Life Processes
• Chapter 7 Control and Coordination
• Chapter 8 How do Organisms Reproduce?
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• Chapter 12 Electricity
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Access Chapter-wise NCERT Solutions for Class 10 Science – Light Reflection and Refraction

Questions Page: 168

1. Define the principal focus of a concave mirror.

Light rays that are parallel to the principal axis of a concave mirror converge at a specific point on its principal axis after reflecting from the mirror. This point is called the principal focus of the concave mirror.

2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length?

Radius of curvature (R) = 20 cm

Radius of curvature of the spherical mirror = 2 × Focal length (f)

f= R/2 = 20 / 2 = 10

Therefore, the focal length of the spherical mirror is 10 cm.

3. Name the mirror that can give an erect and enlarged image of an object.

The mirror that can give an erect and enlarged image of an object is a Concave Mirror.

4. Why do we prefer a convex mirror as a rear-view mirror in vehicles?

A convex mirror is preferred as a rear-view mirror in cars and vehicles as it gives a wider field of view, which helps the driver see most of the traffic behind him. Convex mirrors always form an erect, virtual, and diminished image of the objects placed in front of it.

Page No: 171

1. Find the focal length of a convex mirror whose radius of curvature is 32 cm.

Radius of curvature (R) = 32 cm

Radius of curvature = 2 × Focal length (f)

f = R/2 = 32/2 = 16

Therefore, the focal length of the given convex mirror is 16 cm.

2. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?

Magnification produced by a spherical mirror:

Object distance (u) = – 10 cm

v = 3 × (- 10) = – 30 cm

Therefore, the negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.

Page No: 176

1. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?

The light ray bends towards the normal. When a light ray enters from an optically rarer medium (which has a low refractive index) to an optically denser medium (which has a high refractive index), its speed slows down and bends towards the normal. As water is optically denser than air, a ray of light entering from air into water will bend towards the normal.

2. Light enters from air to glass, having a refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 x 10 8 ms -1 .

Refractive index of a medium (nm) = Speed of light in vacuum/Speed of light in the medium

Speed of light in vacuum (c) = 3 × 10 8 m/s

Refractive index of glass (ng) = 1.50

Speed of light in the glass (v) = Speed of light in vacuum/ Refractive index of glass

=3 × 10 8 /1.50 = 2x 10 8 ms -1 .

3. Find out, from the table, the medium having the highest optical density. Also, find the medium with the lowest optical density.

Lowest optical density = Air

Highest optical density = Diamond

The optical density of a medium is directly related to its refractive index. A medium with the highest refractive index will have the highest optical density and vice-versa.

It can be observed from the table that air and diamond, respectively have the lowest and highest refractive index. Hence, air has the lowest optical density and diamond has the highest optical density.

4. You are given kerosene, turpentine and water. In which of these does the light travel fastest? Use the information given in the table.

Light travels faster in water as compared to kerosene & turpentine, as the refractive index of water is lower than that of kerosene and turpentine. The speed of light is inversely proportional to the refractive index.

5. The refractive index of diamond is 2.42. What is the meaning of this statement?

A diamond has a refractive index of 2.42, which means that the speed of light in a diamond will reduce by a factor of 2.42 as compared to its speed in the air.

In other words, the speed of light in a diamond is 1/2.42 times the speed of light in a vacuum.

Page No: 184

1. Define 1 dioptre of power of a lens.

Dioptre is the SI unit of power of lens is denoted by the letter D. 1 dioptre can be defined as the power of a lens of focal length 1 metre.

2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.

The position of the image should be at 2F since the image is real and the same size.

It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Therefore, the needle is placed in front of the lens at a distance of 50 cm.

Object distance (u) = – 50 cm

Image distance, (v) = 50 cm

Focal length = f

According to the lens formula,

3. Find the power of a concave lens of focal length 2 m.

The focal length of the concave lens (f) = 2 m

Power of lens (P) = 1/f = 1/ (-2) = -0.5D

Page No: 185

1. Which one of the following materials cannot be used to make a lens?

(c) Plastic

Answer –

(d) Clay cannot be used to make a lens because if the lens is made up of clay, the light rays cannot pass through it

2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?

(a) Between the principal focus and the centre of curvature

(b) At the centre of curvature

(c) Beyond the centre of curvature

(d) Between the pole of the mirror and its principal focus.

(d) The position of the object should be between the pole of the mirror and its principal focus.

3. Where should an object be placed in front of a convex lens to get a real image of the size of the object?

(a) At the principal focus of the lens

(b) At twice the focal length

(c) At infinity

(d) Between the optical centre of the lens and its principal focus.

(b) The object should be placed at twice the focal length

4. A spherical mirror and a thin spherical lens have a focal length of -15 cm. The mirror and the lens are likely to be

(a) both concave

(b) both convex

(c) the mirror is concave, and the lens is convex

(d) the mirror is convex, but the lens is concave

(a) Both are likely to be concave.

Page No: 186

5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be

(b) concave

(d) either plane or convex

(d) The mirrors are likely to be either plane or convex

6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary?

(a) A convex lens of focal length 50 cm

(b) A concave lens of focal length 50 cm

(c) A convex lens of focal length 5 cm

(d) A concave lens of focal length 5 cm

(c) A convex lens of focal length 5 cm can be used while reading small letters found in a dictionary

7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.

Range of the distance of the object = 0 to 15 cm from the pole of the mirror.

Nature of the image = virtual, erect, and larger than the object.

8. Name the type of mirror used in the following situations.

(a) Headlights of a car

(b) Side/rear-view mirror of a vehicle

(c) Solar furnace

Support your answer with a reason.

(a) Concave Mirror: Concave mirrors can produce a powerful parallel beam of light when the light source is placed at their principal focus.

(b) Convex Mirror: Because of its largest field of view.

(c) Concave Mirror: Because it concentrates the parallel rays of the sun at a principal focus.

9. One-half of a convex lens is covered with black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.

Yes, it will produce a complete image of the object, as shown in the figure. This can be verified experimentally by observing the image of a distant object, like a tree on a screen, when the lower half of the lens is covered with black paper. However, the intensity or brightness of the image will reduce.

10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.

Height of the object, h 0 = 5 cm

Distance of the object from converging lens, u = -25 cm

Focal length of a converging lens, f = 10 cm

Using the lens formula,

Thus, the image is inverted and formed at a distance of 16.7 cm behind the lens and measures 3.3 cm. The ray diagram is shown below.

11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.

Focal length of concave lens (OF 1 ), f = – 15 cm

Image distance, v= – 10 cm

The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.

12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Focal length of convex mirror (f) = +15 cm

According to the mirror formula,

The image is located at a distance of 6 cm from the mirror on the other side of the mirror.

The positive and a value of less than 1 magnification indicates that the image formed is virtual, erect, and diminished.

13. The magnification produced by a plane mirror is +1. What does this mean?

The positive sign means an image formed by a plane mirror is virtual and erect. Since the magnification is 1, it means that the size of the image is equal to the size of the object.

14. An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.

Object distance (u) = – 20 cm

Object height (h) = 5 cm

Radius of curvature (R) = 30 cm

Radius of curvature = 2 × Focal length

The positive value of image height indicates that the image formed is erect.

Hence, the image formed is erect, virtual, and smaller in size.

15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and nature of the image.

Object distance (u) = – 27 cm

Object height (h) = 7 cm

Focal length (f) = – 18 cm

The negative value of image height indicates that the image formed is inverted.

16. Find the focal length of a lens of power -2.0 D. What type of lens is this?

Power of lens (P) = 1/f

f = -1/2 = -0.5 m

A concave lens has a negative focal length. Therefore, it is a concave lens.

17. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?

f = 1/1.5 = 10/15 = 0.66 m

A convex lens has a positive focal length. Therefore, it is a convex lens or a converging lens.

NCERT Solutions For Class 10 Science Chapter 10 – Light Reflection and Refraction

Chapter 10 Light Reflection and Refraction are one of the important chapters in Class 10 Science, and the expected marks weightage of the chapter, according to the latest marking scheme is 7 marks. In Chapter 10 of Class 10 Science, students will get well-versed in light phenomena such as refraction and reflection. One will learn about spherical mirrors, image formation and to draw ray diagrams.

Topics covered in this chapter:

• Reflection of Light
• Spherical Mirrors
• Image Formation by Spherical Mirrors
• Representation of Images Formed by Spherical Mirrors Using Ray Diagram – 4 Questions (2 short, 2 long)
• Mirror Formula and Magnification – 2 Questions (2 Numerical)
• Refraction of Light – 5 Questions (1 numerical, 2 Long answers and 1 Short answer)
• Power of Lens – 3 Questions (2 Short answers and 1 numerical)

Have you ever wondered what makes things visible to us? The answer to the question is light. During the day, it is sunlight that helps us see objects. When light falls on an object, it reflects. This reflected ray, when received by our eyes, helps us see things. Numerous wonderful phenomena are associated with light, such as the formation of the rainbow, of stars, and many more. In Chapter 10 Light Reflection and Refraction of Class 10 Science, let us study the phenomena of refraction and reflection using straight-line propagation of light. We shall also try to understand the reflection of light by spherical mirrors in this chapter using the NCERT Solutions from BYJU’S.

Key Features of NCERT Solutions for Class 10 Science Chapter 10 – Light Reflection and Refraction:

• Provides comprehensive answers to all the questions asked in the chapter
• The language used is lucid and can be understood by all
• The information provided is genuine and appropriate
• These solutions can be referred for CBSE exams, Olympiads and other competitive exams
• Concise answers are provided to help students understand better

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CBSE Class 10 Science Case Study Questions Download Free PDF

If you are looking for the CBSE Class 10 Science Case Study Questions in PDF, then you are in the right place. CBSE 10th Class Case Study for the Science Subject is available here. These Case studies can help the students to solve the different types of questions that are based on the case study.

CBSE Board will be asking case study questions based on Science subjects in the upcoming board exams. Thus, it becomes an essential resource to study. 

The Science Subject case study for class 10th covers a wide range of chapters from the Science. Students willing to score good marks in their board exams can use it. The questions are highly interactive and it allows students to use their thoughts and skills to solve such kinds of questions.

Case Study Questions Class 10 Science

In board exams, students will find the questions based on assertion and reasoning . Also, there will be a few questions based on case studies. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

• Case Study Questions for Chapter 1 Chemical Reactions and Equations
• Case Study Questions for Chapter 2 Acids, Bases, and Salts
• Case Study Questions for Chapter 3 Metals and Non-Metals
• Case Study Questions for Chapter 4 Carbon and Its Compounds
• Case Study Questions for Chapter 5 Periodic Classification of elements
• Case Study Questions for Chapter 6 Life Processes
• Case Study Questions for Chapter 7 Control and Coordination
• Case Study Questions for Chapter 8 How do organisms reproduce?
• Case Study Questions for Chapter 9 Heredity and Evolution
• Case Study Questions for Chapter 10 Light reflection and refraction
• Case Study Questions for Chapter 11 Human eye and colorful world
• Case Study Questions for Chapter 12 Electricity
• Case Study Questions for Chapter 13 Magnetic effects of current
• Case Study Questions for Chapter 15 Our Environment

The above  Case studies  for CBSE Class 10 Science will help you to score good marks in the Case Study questions that have been coming in your examinations. These CBSE Class 10 Science Case Study have been developed by experts of cbseexperts.com   for benefit of Class 10 students.

Class 10 Science Assertion and Reason Questions

Case Study Type Questions in Science Class 10

Case Study Type Questions in Science Class 10 include the information or data. Students willing to solve them are required to read the passage carefully and then solve them. While solving the paragraph the ideal way is to highlight the key information or given data.

Because later it will ease them to write the final answers. Science Case study type questions consist of 4 to 5 questions that should be answered in an MCQ manner. 

While reading the paragraph students will get the clue in between about the possible answer of the question. They should definitely highlight those questions. This is the best way to solve such kind of Case study Type Questions.

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Chapter 10 Light Reflection And Refraction

Extra questions for class 10 science chapter 10 light – reflection and refraction.

Get extra questions for Class 10 Science Chapter 10 Light – Reflection And Refraction with PDF. Our subject expert prepared these solutions as per the latest NCERT textbook. These extra questions will be helpful to revise the important topics and concepts. You can easily download all the questions and answers in PDF format from our app.

CBSE Class 10th - SCIENCE : Chapterwise Case Study Question & Solution

In board exams, students will find the questions based on assertion and reasoning. Also, there will be a few questions based on case studies. In that, a paragraph will be given, and then the MCQ questions based on it will be asked. For Science subjects, there would be 5 case-based sub-parts questions, wherein a student has to attempt 4 sub-part questions.

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NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction

September 27, 2019 by Veerendra

NCERT Solutions For Class 10 Science Chapter 10 Light Reflection and Refraction : In this article, you candidates can find light reflection and refraction class 10 NCERT solutions. Working on the light chapter of class 10 NCERT solutions will help candidates to build a strong foundation over the subject Physics. Knowing light reflection and refraction class 10 questions and answers will help students of class 10 to bag a decent score in class 10 board exams as well.

Along with NCERT Solutions For Class 10 Science Chapter 10 Light Reflection and Refraction candidates can also find light reflection and refraction class 10 numericals questions in this article.  Go through them will help candidates get a clear idea about how to approach the problems which in turn helps you to solve them in the most efficient way. So why wait? Read on to find out everything about light reflection and refraction class 10 important questions with answers here.

Before getting into the details of  NCERT Solutions For Class 10 Science Chapter 10 Light Reflection and Refraction,  let’s have an overview of topics and subtopics under NCERT class 10 science book activities solutions chapter 10:

• Light – Reflection And Refraction
• Reflection Of Light
• Spherical Mirrors
• Refraction Of Light

Free download NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.

• प्रकाश-परावर्तन एवं अपवर्तन कक्षा 10 विज्ञान हिंदी में
• Class 10 Light Reflection and Refraction Important Questions
• Light Reflection and Refraction Class 10 Notes
• Light Reflection and Refraction NCERT Exemplar Solutions

Class 10 Science Light Reflection and Refraction Mind Map

Ncert solutions for class 10 science chapter 10 intext questions.

Page Number: 168

Question 1 Define the principal focus of a concave mirror. Answer: The principal focus of a concave mirror is a point on its principal axis to which all the light rays which are parallel and close to the axis, converge after reflection from the concave mirror.

Question 2 The radius of curvature of a spherical mirror is 20 cm. What is its focal length? Answer: Focal length = \(\frac { 1 }{ 2 }\) x Radius of curvature = \(\frac { 1 }{ 2 }\) x 20 cm = 10 cm

Question 3 Name a mirror that can give an erect and enlarged image of an object. Answer: Concave mirror.

Question 4 Why do we prefer a convex mirror as a rear-view mirror in vehicles ? Answer: We prefer a convex mirror as a rear-view mirror in vehicles because of two reasons :

•  A convex mirror always produces an erect image of the objects.
•  The image formed in a convex mirror is highly diminished or much smaller than the object, due to which a convex mirror gives a wide field of view of the traffic behind. A convex mirror enables the driver to view such larger area of the traffic behind him.

Page Number: 171

Question 1 Find the focal length of a convex mirror whose radius of curvature is 32 cm. Solution: R = +32 cm and \(f=\frac { R }{ 2 } =+\frac { 32 }{ 2 } =+16cm\)

Page Number: 176

Question 1 A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal ? Why ? Answer: The light-ray bends towards the normal because the ray of light goes from a rarer medium to a denser medium.

Question 3 Find out, from Table 10.3, the medium having highest optical density. Also find the medium with lowest optical density. Answer: From table 10.3, diamond has highest refractive index (= 2.42), so it has highest optical density. Air has lowest refractive index (= 1.0003), so it has lowest optical density.

Question 4 You are given kerosene, turpentine and water. In which of these does the light travel fastest ? Use the information given in Table 10.3. Answer: For kerosene, n = 1.44 For turpentine, n = 1.47 For water, n = 1.33 Because water has the lowest refractive index, therefore light travels fastest in this optically rarer medium than kerosene and turpentine oil.

Question 5 The refractive index of diamond is 2.42. What is the meaning of this statement? Answer: By saying that the refractive index of diamond is 2.42, we mean that the speed of light in diamond is lower by a factor of 2.42 relative to that in vacuum.

Page Number: 184

Question 1 Define 1 dioptre of power of a lens. Answer: One dioptre is the power of a lens whose focal length is 1 metre.

NCERT Solutions for Class 10 Science Chapter 10 Textbook Chapter End Questions

Question 1 Which one of the following materials cannot be used to make a lens ? (a) Water (b) Glass (c) Plastic (d) Clay Answer: (d) Clay

Question 2 The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object ? (a) Between the principal focus and the centre of curvature (b) At the centre of curvature (c) Beyond the centre of curvature (d) Between the pole of the mirror and its principal focus. Answer: (d) Between the pole of the mirror and its principal focus.

Question 3 Where should an object be placed in front of a convex lens to get a real image of the size of the object ? (a) At the principal focus of the lens (b) At twice the focal length (c) At infinity (d) Between the optical centre of the lens and its principal focus. Answer: (b) At twice the focal length.

Question 4 A spherical mirror and a thin spherical lens have each a focal length of -15 cm. The mirror and the lens are likely to be : (a) Both concave. (b) Both convex. (c) the mirror is concave and the lens is convex. (d) the mirror is convex, but the lens is concave. Answer: (a) Both concave

Question 5 No matter how far you stand from mirror, your image appears erect. The mirror is likely to be (a) plane (b) concave (c) convex (d) either plane or convex. Answer: (d) Either plane or convex.

Question 6 Which of the following lenses would you prefer to use while reading small letters found in a dictionary ? (a) A convex lens of focal length 50 cm. (b) A concave lens of focal length 50 cm. (c) A convex lens of focal length 5 cm. (d) A concave lens of focal length 5 cm. Answer: (c) A convex lens of focal length 5 cm.

Question 8 Name the type of mirror used in the following situations. (a) Headlights of a car. (b) Side/rear-view mirror of a vehicle. (c) Solar furnace. Support your answer with reason. Answer: (a) Concave mirrors are used as reflectors in headlights of cars. When a bulb is located at the focus of the concave mirror, the light rays after reflection from the mirror travel over a large distance as a parallel beam of high intensity.

(b) A convex mirror is used as a side/rear-view mirror of a vehicle because

• A convex mirror always forms an erect, virtual and diminished image of an object placed anywhere in front it.
• A convex mirror has a wider field of view than a plane mirror of the same size.

(c) Large concave mirrors are used to concentrate sunlight to produce heat in solar furnaces.

Question 13 The magnification produced by a plane mirror is +1. What does this mean ? Answer: Since magnification, \(m=\frac { { h }^{ ‘ } }{ h } =\frac { -\nu }{ u }\). Given, m = +1, so h’ = h and ν = -u

(i) m = 1 indicates the size of image is same as that of object. (ii) positive sign of m indicates that an erect image is formed.

The opposite signs of ν and u indicate that image is formed on the other side of the mirror from where the object is placed i.e., image is formed behind the mirror and thus image formed is virtual.

Reflection of light by curved surfaces; Images formed by spherical mirrors, center of curvature, principal axis, principal focus, focal length, mirror formula (Derivation not required), magnification. Refraction; laws of refraction, refractive index. Refraction of light by spherical lens; Image formed by spherical lenses; Lens formula (Derivation not required); Magnification. Power of a lens;

Formulae Handbook for Class 10 Maths and Science

Question 1. Define the principal focus of a concave mirror? Answer: Light rays that are parallel to the principal axis of a concave mirror converge at a specific point on its principal axis after reflecting from the mirror. This point is known as the principal focus of the concave mirror.

Question 2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length? Answer: Radius of curvature, R = 20 cm Radius of curvature of a spherical mirror = 2 x Focal length (f) f = R/2 = 20/2 =10cm

More Resources for CBSE Class 10

NCERT Solutions

• NCERT Solutions for Class 10 Science
• NCERT Solutions for Class 10 Maths
• NCERT Solutions for Class 10 Social
• NCERT Solutions for Class 10 English
• NCERT Solutions for Class 10 Hindi
• NCERT Solutions for Class 10 Sanskrit
• NCERT Solutions for Class 10 Foundation of IT
• RD Sharma Class 10 Solutions

Question 3. Name the mirror that can give an erect and enlarged image of an object. Answer: When an object is placed between the pole and the principal focus of a concave mirror, the image formed is virtual, erect, and enlarged.

Download NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction PDF

Question 4. Why do we prefer a convex mirror as a rear-view mirror in vehicles? Answer: Convex mirrors give a virtual, erect, and diminished image of the objects placed in front of them. They are preferred as a rear-view mirror in vehicles because they give a wider field of view, which allows the driver to see most of the traffic behind him.

Question 1. Find the focal length of a convex mirror whose radius of curvature is 32 cm. Answer: Radius of curvature, R = 32 cm Radius of curvature = 2 x Focal length (f) R = 2f f = R/2 = 32/2 = 16cm Hence, the focal length of the given convex mirror is 16 cm.

Question 2. A concave mirror produces three times magnified (enlarged) real image of object placed at 10 cm in front of it. Where is the image located? Answer: Given, u = – 10 cm Since image is real inverted so, m = -3 m = -v / u ⇒  -3 = -v/ -10 v= – 30 cm Negative sign indicates the image will be real and image is formed at 30 cm in front of the mirror.

Question 1. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why? Answer: The light ray bends towards the normal. When a ray of light travels from an optically rarer medium to an optically denser medium, it gets bent towards the normal. Since water is optically denser than air, a ray of light travelling from air into the water will bend towards the normal.

Question 1. Define one dioptre of power of a lens? Answer: One dioptre is the power Of a lens Of focal length 1m. Power of lens is defined as the reciprocal of its focal length. If P is the power of a lens of focal length F in metres, then P = 1/ f (in meters) The S.I. unit of power of a lens is Dioptre. It is denoted by D. 1 dioptre is defined as the power of a lens of focal length 1 metre. 1 D = 1 m−1

Question 2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the lens if the image is equal to the size of the object? Also find the power of the lens. Answer: v = + 50 cm Since image is real and of same size. The position of image should be double the focal length. Hence, the object should be at 2f. V = 2f = 50, f = 25 cm. Power = 1/f = 100/25 = 4D

Question 1. Which one of the following materials cannot be used to make a lens? (a) Water (b) Glass (c) Plastic (d) Clay Answer: (d) Clay

Question 2. The ¡mage formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object? (a) Between the principal focus and the centre of Curvature (b) At the centre of curvature (c) Beyond the centre of curvature (d) Between the pole of the mirror and Its principal focus. Answer: (d) Between the pole of the mirror and its principal focus.

Question 3. Where should an object b. placed In front of a convex lens to get a real image of the size of the object? (a) At the principal focus of the lens (b) At twice the focal length (c) At infinity (d) Between the optical centre of the lens and its principal focus Answer: (b) At twice the focal length

Question 4. A spherical mirror and a thin spherical lens have each a focal length of 15 cm. The mirror and the lens are likely to be: (a) both concave (b) both convex (c) the mirror is concave, but the lens is convex (d) the mirror is convex, but the lens is concave Answer: (a) Both concave.

Question 5. No matter how far you stand from a mirror, your Image appears erect. The mirror is likely to be (a) plane (b) concave (c) convex (d) Either plane or convex Answer: (d) Either plane or convex.

Question 6. Which of the following lenses would you prefer to use while reading small letters found ¡n a dictionary? (a) A convex lens of focal length 50cm (b) A concave lens of focal length 50cm (c) A convex lens of focal length 5 cm (d) A concave lens of focal length 5 cm. Answer: (c) A convex lens of focal length 5 cm.

Question 8. Name the type of mirror used in the following situations. (a) Headlights of a car (b) Side/rear-view mirror of a vehicle (c) Solar furnace Support your answer with reason. Answer: (a) Concave mirror, to get powerful and parallel beams of light. (b) Convex mirror because it always gives an erect image and enables the driver to view much larger area. (c) Concave or parabolic mirror because it can concentrate sunlight at the focus to produce heat in the solar furnace.

Question 9. One half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations. Answer: Yes, even when one half of the lens is covered with a black paper, complete image of the object will be formed. Take a convex lens and focus the light from a distant object onto a screen. As expected an image (sharp) is formed at a distance equal to the focal length Cover the lower or the upper half of the lens and focus the light from the same object onto the same screen. You will be able to get a sharp image again; however the brightness of the image will be less in the second case. The same effect w,ll be seen even if the lens is half covered with black strips.

Question 13. The magnification produced by a plane mirror is +1. What does this mean? Answer: This means that size of the image is equal to the size of the object.

Multiple Choice Questions (MCQs) [1 mark each]

Question 1. Hold a highly polished steel spoon curved inwards close to your face and move it slowly away from your face. What will you observe? (a) Enlarged and erect image of your face (b) Smaller and inverted image of your face (c) Smaller and erect image of your face (d) Enlarged and inverted image of your face Answer: (b) The inner curved surface of a highly polished steel spoon acts as a concave mirror. When the spoon is at a small distance from the face such that, the object lies between pole and focus of concave mirror, so an enlarged and erect image of your face will be observed but as the spoon is slowly moved away from the face, the image becomes smaller and appears inverted.

Question 2. Which one of the following materials cannot be used to make a lens? [NCERT] (a) Water (b) Glass (c) Plastic (d) Clay Answer: (d) Clay can never be transparent, so it cannot be used to make lens.

Question 3. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be [NCERT] (a) plane (b) concave (c) convex (d) either plane or convex Answer: (d) Plane mirrors and convex mirrors always form the erect images.

Question 4. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object? [NCERT] (a) Between principal focus and centre of curvature (b) At centre of curvature (c) Beyond centre of curvature (d) Between pole of the mirror and its principal focus Answer: (d)

Question 6. A spherical mirror and a thin spherical lens have each of a focal length -15 cm. The mirror and lens are likely to be [NCERT] (a) both concave (b) both convex (c) mirror is concave and lens is convex (d) mirror is convex and lens is concave Answer: (a) The focal length is taken as negative for both concave mirror and concave lens.

Question 8. Under which of the following conditions, a concave mirror can form an image larger than the actual object? [NCERT Exemplar] (a) When an object is kept at a distance equal to its radius of curvature (b) When an object is kept at a distance less than its focal length (c) When an object is placed between the focus and centre of curvature (d) When an object is kept at a distance greater than its radius of curvature Answer: (c) A concave mirror can form an image enlarged, real and inverted than the actual object, beyond centre of curvature (C) when object is placed between the focus (F) and centre of curvature.

Question 13. Which of the following statement is true? [NCERT Exemplar] (a) A convex lens has 4D power having a focal length 0.25 m (b) A convex lens has 4D power having a focal length -0.25 m (c) A concave lens has 4D power having a focal length 0.25 m (d) A concave lens has 4D power having a focal length -0.25 m Answer: (a) The power P of a lens of focal length f is given by P = 1/f, where f is the focal length in metre and P is the power in dioptre. P= 1/f or f = 1/P = 1/4 = 0.25 m

Question 14. Magnification produced by a rear view mirror fitted in vehicles [NCERT Exemplar] (a) is less than one (b) is more than one (c) is equal to one (d) can be more than or less than one depending upon the position of the object in front of it. Answer: (a) The convex mirror forms virtual, erect and diminished image of the object and rear view mirror also form same type of image. Therefore, magnification (m) produced by a rear view mirror fitted in vehicles is less than one, i.e. m < 1.

Question 15. Rays from the Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed, so that size of its image is equal to the size of the object? [NCERT Exemplar] (a) 15 cm in front of the mirror (b) 30 cm in front of the mirror (c) between 15 cm and 30 cm in front of the mirror (d) more than 30 cm in front of the mirror Answer: (b) The rays from the Sun, i.e. from infinity, are parallel to principal axis after reflection converge at a point is known as focus. Therefore, focal length if) of concave mirror is 15 cm. And we know that, same size, real and inverted image is formed by concave mirror when object is placed at focus 2 A or centre of curvature, so to form same size of image, object will be placed at 15 x 2 =30 cm.

Question 17. You are given water, mustard oil, glycerine and kerosene. In which of these media, a ray of light incident obliquely at same angle would bend the most? [NCERT Exemplar] (a) Kerosene (b) Water (c) Mustard oil (d) Glycerine Answer: (d) The given material having their refractive index as kerosene is 1.44, water is 1.33, mustard oil is 1.46 and glycerine is 1.74. Thus, glycerine is most optically denser and hence have the largest refractive index. Therefore, ray of light bend most in glycerine.

Question 18. A student placed a light bulb in midway between the two plane mirrors inclined at an angle of 60°. How many images will be observed by him? (a) 4 (b) 6 (c) 5 (d) 8 Answer: (c) Number of images formed by two plane mirrors inclined at an angle 60° when a light bulb is placed in midway between them is N = 360°/60° – 1 = 6 – 1 = 5

Question 19. Where should an object be placed in front of a convex lens to get a real image of the size of the object? [NCERT] (a) At the principal focus of the lens (b) At twice the focal length (c) At infinity (d) Between the optical centre of the lens and its principal focus Answer: (b) To set the real image of the size of the object, it should be placed at twice the focal length of a convex lens.

Question 20. Which of the following lenses would you prefer to use while reading small letters found in dictionary? [NCERT] (a) A convex lens of focal length 50 cm (b) A concave lens of focal length 50 cm (c) A convex lens of focal length 5 cm (d) A concave lens of focal length 5 cm Answer: (c) Convex lens is used as magnifying glass. For better performance its focal length should be small.

NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction (Hindi Medium)

LIGHT REFLECTION & REFRACTION Form of energy produces the sensation of vision in eyes. Light (EM waves wave-length 400 nm to 750 nm). The path of light (always travel in straight line) is ray of light

Characteristics of light

• Rectilinear propagation of light
• Light travels with a speed of 3 × 10 8 m/s in air/vaccum.
• Speed of light depends on the medium
• Light shows behaviour such as reflection, refraction, interference, diffraction, polarisation etc.

Law of Refraction Refraction of light:  Bending of light ray while passing from one medium to another medium

• A ray of light bends towards the normal, while going from rarer to denser medium
• And bends away from the normal while going from denser to rarer medium
• Refraction of light takes place because the speed of light is different in the two media

Total internal Reflection :  Ray totally reflected back to denser medium Phenomena based on TIR

• Mirage – optical illusion in deserts
• Looming – optical illusion in cold countries
• Optical fibre
• Brilliance of diamond

Necessary conditions for TIR (i )  Ray of light must travel from denser to rarer medium (ii)  ∠i > ∠c for two media

Critical angle (c)  Angle i in denser medium for which angle of refraction in rarer medium is 90° μ = \(\frac{1}{\sin C}\)

Snell’s law μ = \(\frac{\sin i}{\sin r}\) For two media 1 μ 2 = \(\frac{\mu_{2}}{\mu_{1}}=\frac{\sin i}{\sin r}\)

Reflection of light:  Turning back of light in the same medium after striking the reflecting surface or mirror

• After reflection, velocity, frequency and wavelength of light remains same but intensity decreases
• If reflection takes place from denser medium then phase change ‘π’

Regular Reflection

Reflection on smooth surface.

Diffuse  Reflection Reflection on rough surface.

Laws of Reflection

The incident ray the normal and the reflected ray all lie in the same plane The angle of incidence (i) is always equal to angle of reflection (r) i.e., ∠i = ∠r

Mirror formula \(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\) When two plane mirrors are held at an angle 9 with their reflecting surfaces facing each other and an object is placed between them, images are formed by successive reflections. . f concave = negative f convex = positive and f plane = ∞

Relation between focal length (f) and radius of curvature, R f = \(\frac{R}{2}\)

Magnification m = \(\frac{\mathrm{v}}{\mathrm{u}}=\frac{\text { height of image }}{\text { height of object }}\) m = \(\frac{f}{f-u}=\frac{f-v}{f}\)

The incident ray, the normal and the refracted ray all lie in the same plane Refractive index, μ = \(\frac{c}{v}=\frac{\text { real depth }}{\text { apparent depth }}\)

Plane Mirror

Is a looking glass, highly polished on one surface.

• Forms virtual and erect image
• Distance of object from mirror = distance of image from mirror.
• The size of the image is same as object.
• Image is laterally inverted.
• Used in kaleidoscope periscope, etc.

Concave Mirror Spherical glass polished on the outside. It is also known as a converging mirror.

• Images produced are always real, inverted, can be enlarged based on the position except when object is placed between pole and focus.
• Uses: Make-up and shaving mirrors, dentist mirror, in floodlight etc.

Image formation by a convex mirror for different positions of the object

Convex Mirror Spherical glass polished inside. It is also known as diverging mirror.

• It forms virtual, upright and small images.
• Uses: for security’ purposes, in vehicles as rear- view mirror and street lighting.

Image formation by a concave mirror for different positions of the object

Atmospheric Refraction

Earth’s atmosphere is thin at the top and dense at the bottom, thus leads to refraction of light, μ = c/v

• Twinkling of stars
• Advanced sunrise and delayed sunset

Refraction Through a Glass Slab x = \(\frac{t \sin (i-r)}{\cos r}\) ∴ x ∝ μ

Power of a lens

P = \(\frac{1}{f(\text { in metre })}\) Unit of power of lens is diopter (D) P convex → Positive P concave → Negative and P plane → Zero

Lens Piece of transparent material with two refracting surfaces, at least one is curved and refractive index should different as that of the surrounding.

Lens formula \(\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\) f convex → negative f concave → positive and f plane → ∞

Concave Lens Cental portion of lens is thinner than marginal. It as also known as diverging lens.

Convex Lens Central portion of lens is thicker than marginal. It is also known us converging lens.

Magnification Ratio of distance of image to the distance of object from the optical centre. Also equal to height of image to the height of object m = \(\frac{\mathrm{I}}{\mathrm{o}}=\frac{\mathrm{v}}{\mathrm{u}}=\frac{\mathrm{h}_{\mathrm{I}}}{\mathrm{h}_{\mathrm{o}}}\)

Nature, position and relative size of the image formed by a concave lens for various position of the object

Nature, position and relative size of the image formed by a convex lens for various positions of the object

Now that you are provided all the necessary information regarding NCERT Solutions For Class 10 Science Chapter 10 Light Reflection and Refraction  and we hope this detailed article on light reflection and refraction class 10 NCERT solutions is helpful. If you have any questions related to this article, kindly ask your questions through the comment section below and we will get back to you as soon as possible.

NCERT Solutions for Class 10 Science All Chapters

• Chapter 1 Chemical Reactions and Equations
• Chapter 2 Acids, Bases and Salts
• Chapter 3 Metals and Non-metals
• Chapter 4 Carbon and Its Compounds
• Chapter 5 Periodic Classification of Elements
• Chapter 6 Life Processes
• Chapter 7 Control and Coordination
• Chapter 8 How do Organisms Reproduce?
• Chapter 9 Heredity and Evolution
• Chapter 10 Light Reflection and Refraction
• Chapter 11 Human Eye and Colourful World
• Chapter 12 Electricity
• Chapter 13 Magnetic Effects of Electric Current
• Chapter 14 Sources of Energy
• Chapter 15 Our Environment
• Chapter 16 Management of Natural Resources

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