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Why do I get the "Subscripted assignment dimension mismatch" error message?
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Error: subscripted assignment dimension mismatch during convolution.
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How can i solve this? Subscripted assignment dimension mismatch
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Matlab Error: Subscripted assignment dimension mismatch
I am trying to convert decimal number to binary. It works for regular decimal numbers. However, when I enter (25.10) I get the subscripted error.
My code below.
- 1 Possible duplicate of convert 9.2532 decimal into binary matlab – Sardar Usama Commented Jan 16, 2019 at 16:01
- What should the output be for input 25.10 ? – Luis Mendo Commented Jan 16, 2019 at 16:21
- @LuisMendo converting a decimal number to binary... my function is having an issue with decimal points ... – Frank Boccia Commented Jan 16, 2019 at 17:02
- 1 As a side note, Matlab has the function dec2bin, with dec2bin(25.10) yielding '11001' (which is 25). I don't think your code is able to produce the binary form of the decimal part (0.10 = 0*0.5+0*0.25+0*0.125+1*0.0625...) yielding '0.0001...'. Maybe provide some context as to why you'd like to convert a decimal number. – Mefitico Commented Jan 16, 2019 at 17:15
- 2 @FrankBoccia What approach is your code using? Have you traced the execution using the debugger to see the values of the variables when the error occurs? What do you expect binary(i) = num2str(r(i)); to do (or is it binary(i) = num2str(r); ?) – beaker Commented Jan 16, 2019 at 17:45
Assuming the line with the error is indeed:
Then, when calling the function with argument 25.10, before reaching this line we have:
That's why the attribution
Does not work. In Matlab, binary(1) is a 1x1 char array. You are trying to fit a 1x3 char array ('1.1') to it.
- How do I fix this error? Do I have to make another variable a double to store this information? – Frank Boccia Commented Jan 17, 2019 at 2:48
- 1 You should have rounded r(i) to have it equal to 1 and ignore the decimal part. Then you need a different logic to work with the decimal. Recalling my previous comment as a hint: (0.10 = 0*0.5+0*0.25+0*0.125+1*0.0625...) yielding '0.0001...' – Mefitico Commented Jan 17, 2019 at 10:43
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In this case, 'A' has size 2x3, that is, 2 rows and 3 columns. The vector 'B' has size 1x4, 1 row and 4 columns. The assignment statement attempts to replace the second row of 'A' with the row vector 'B', but this is not possible because 'B' has 4 columns, and 'A' only has 3 columns.
For the case where you are assigning values for every pairwise combination, here are a couple of the ways you can do it: Break up the assignment into 3 steps, one for each plane in the third dimension: new_img(rows,cols,1) = curMean(1); %# Assignment for the first plane. new_img(rows,cols,2) = curMean(2); %# Assignment for the second plane.
watermarked_row = reshape (transpose (watermarked), 1, numel (watermarked)); EDITED: And together with Sean de's addition: If you image is a [Width x Height x 3] 3D array, convert it to a grey scale at first: Theme. Copy. watermarked = rgb2gray (watermarked); Or operate on a single color channel only, e.g. red: Theme.
Subscripted assignment dimension mismatch.. Learn more about image processing MATLAB
Learn more about subscripted assignment dimension mismatch., subscripted assignment dimension mismatch, subscripted assignment dimension mismatch for loop Here is the code that I'm getting the error: for z=1:length(X) V(z)=[X(z):Y]; end where X is a 1x81 matrix and Y is an integer
Error : Subscripted assignment dimension mismatch.. Learn more about error, subscript assignment
Subscripted assignment dimension mismatch. Learn more about subscripted assignment dimension mismatch Dear All, I have recently upgraded to R2016b (from R2013b).
" Subscripted assignment dimension mismatch." Follow 13 views (last 30 days) Show older comments. ... When Matlab stops at the error, check the used indices. In other words: Learn to use the debugger. It is the best friend of the programmer - even better than this forum.
Copy. function s=my_function (A) hand=@ (x) Multiply_by_Ar (A,x); s=eigs (hand,1); The function Multiply_by_Ar returns, for a given A and x, the vector Ar*x, where the matrix Ar is related to A, but not equal to it. I then make a function handle which is basically multiplying by Ar and use the eigs function. It returns the problem.
In this case, 'A' has size 2x3, that is, 2 rows and 3 columns. The vector 'B' has size 1x4, 1 row and 4 columns. The assignment statement attempts to replace the second row of 'A' with the row vector 'B', but this is not possible because 'B' has 4 columns, and 'A' only has 3 columns.
Answers (1) As a debugging step, assign the output of the extraction to a variable, and then check the size of the variable compared to the size of your features array. Note: your commented out img =imresize (img, .5); would not resize all of the images to the same size: it would resize them to half of the size they were.
However I think you are plotting the wrong thing. Your Y axis is one of the boundary conditions, but the Y axis in the paper is .The paper looks like it is plotting for 3 different δ values, but you are only using one δ value. You asked to plot for all values for all timepoints; in the paper the x axis is and it is not obvious to me that time comes into the plot at all.
Error: subscripted assignment dimension mismatch... Learn more about convolution, error
S is currently 1 x 3, so that is an assignment to S(2, 1:3) which requires the right hand side to be a scalar, or a vector that is 3 elements long. But the right hand side is 2 x 2. If you had initialized S as zeros(1,4) then the 2 x 2 on the right hand side would be the correct number of elements, but it would be the wrong shape to assign to a ...
Why do I get the "Subscripted assignment... Learn more about subscripted, assignment, dimension, mismatch MATLAB
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0. Your problem comes from the r vector: it sometimes is empty because the polynomial doesn't have roots. Then r is a 0x1 vector, and you're assigning it to a 2x1 vector ( r(:,c1,c2,c3) is a 2x1 vector because the first time you assign r to it, Matlab creates the matrix rr and initializes its size). You would need a check on the existence of ...
Subscripted assignment dimension mismatch.. Learn more about matlab error
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