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5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

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Eureka Math Grade 5 Module 5 Lesson 6 Answer Key

Engage ny eureka math 5th grade module 5 lesson 6 answer key, eureka math grade 5 module 5 lesson 6 problem set answer key.

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 1

Volume = length x width x height

V= 14 x 10 x 3

V = 420 cubic centimetres.

Solution strategy : I added the height of 2 cubes to get 10 cm and applied volume formula

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 2

V = 7 x 4 x 3

V = 84 cubic inches

Volume = 15 x 4 x 6

V = 360 cubic inches

Total volume = 84 + 360 = 444 cubic inches

Solution strategy = Calculated volume of each prism individually.

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 3

V = 4 x3 x 4

V = 48 cubic centimeters

Volume = 10 x 3 x 2

V = 60 cubic centimeters

Total volume = 48  + 60

V = 108 cubic centimetres.

Solution strategy:

The width of the shape 1 is 10 – 6 = 4 cm ,

Then i calculate dthe volume individually and added them.

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 4

V = 8 x 3 x 6

V = 144 cubic centimeters

Volume = 10 X 3 X 6

v = 180 cubic centimeters

Total volume = 144 + 180 = 324 Cubic centimeters

The height of the shape 1. is 12 – 6 = 6 cm

Then I caluculated the volume individually and added them together.

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 5

Let, the small size prisms be A and large sized prisms be B

Given the measurents of prism A =

length = 13, width = 8 and height = 2 inches

Number of A prisms = 6

Now, volume = 13 in x 8 in x 2 in

V = 208 cubic inches

Total volume of 6 prisms(A) =

V = 206 x 6

Also given the measurements of prism B =

Length = 9 in, width = 8 in and height = 18 inches

Volume = 9 in x 8 in x 18 in

Number of prisms B = 2

Volume = 1296 x 2

Now, the total volume of the sculpture =

Volume of prisms A and volume of prisms B

= 1,248 + 2592

Therefore, total volume of sculpture = 3840 cubic inches

Question 3. The combined volume of two identical cubes is 128 cubic centimeters. What is the side length of each cube? Answer:

Given the combined volume of two identical cubes = 128 cubic centimetres

So, 128 / 2 = 64

64 can be written as 4 x 4x 4

Therefore, the each side is 4 cm long.

Engage NY Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key 6

Given, the bae area of tank = 24 sq. cm

The depth of water and oil poured into the tank = 9 cm

Given, the thickness of oil poured = 4 cm

So, 9 – 4 = 5

Now, the volume of water =

Therefore, the volume of the water = 120 cubic cm.

Question 5. Two rectangular prisms have a combined volume of 432 cubic feet. Prism A has half the volume of Prism B. a. What is the volume of Prism A? Prism B? b. If Prism A has a base area of 24 ft2, what is the height of Prism A? c. If Prism B’s base is \(\frac{2}{3}\) the area of Prism A’s base, what is the height of Prism B? Answer:

Given, the combined volume of three prisms = 432 cubic feet,

The prism A has half the volume of prism B

So, the volume of prism A = 144 cubic feet and prism B = 288 cubic fet

Given, if the base area of prism A = 24 sq. feet

Now, height of the prism =

Volume / area

Therefore, the height of prism A = 6 feet

Given , if the prism B’s base = 2/3 of the prism A’s

Now, the height of prism B =

=  16 sq. feet

So, the height of prism B = volume/ area

Therefore, the height of prism B = 18 feet

Eureka Math Grade 5 Module 5 Lesson 6 Exit Ticket Answer Key

Eureka Math 5th Grade Module 5 Lesson 6 Exit Ticket Answer Key 1

Volume of A

= length x width x height

v = 15 X 3 X 3

v = 135 cubic inches

Volume of B =

length x width x height

V = = 9 x 3 x 4

V = 108 cubic inches

Volume of C =

length x width xheight

V = 3 X 3 X 6

V = 54 cubic inches

Total volume = 135 + 108 + 54

Therefore, the total volume of planters = 297 cubic inches.

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 1

1. V= 13 x 2 x 2

V= 52 cubic inches

2. V = 2 x 2 x 5 = 20 cubic inches

Total volume = 52 + 20 = 72 cubic inches.

Solution strategey = 4/2 = 2 , the heigth of the bottom box = 2 inches

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 2

1.  18 x 3 x 2 = 108 cubic centimetres

2.  21 x 9 x 7 = 1326 cubic centimetres

Total volume = 1,431 cubic centimetres.

Calculated each shape volume individually.

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 3

1.  6 x 4  x 3 = 72 cubic mm

2. 11 x 3 x 4 = 132 cubic mm.

3. 3 x 3 x 5 =45 cubic mm.

Total volume =72 + 132 + 45 = 249

Therefore, total volume = 249 cubic mm

Solution strategy :

8 – 5 = 3 So, the width of box is 3 mm

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 4

1.  12 x 4 x 9 = 432 cubic metres

2. 10 x 2 x 2 = 40 cubic metres

Total volume = 432 + 40 = 472

Therefore, total volume = 472 cubic metres.

11 – 9 = 2 , So, the height of the bottom shape is 2 m

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 5

Given, the measurement of shape 1 =

3 inches by 6 inches by 14 inches

Now, volume of box 1 =

V = length X width Xheight

v= 3 X 6 X 14

V =252 cubic inches

Now, there are 2 oxes of same shape so,

2 x 252 =504 cubic inches

2. The measurements of box 2 =

15 inches by 5 inches by 10 inches

Volum =- 15 x 5 x 10

V = 750 cubic inches

Now, total volume = 504 cubic in. + 750 cubic in.

V =1,254 cubic inches.

Question 3. The combined volume of two identical cubes is 250 cubic centimeters. What is the measure of one cube’s edge? Answer:

Given, the combined volume of indentical cubes = 250 cubic centimetres.

250 / 2 = 125 cubic cm.

125 can be written as 5 x 5 x 5

Therefore, the measurement of one cube’s edge = 5 cm

Eureka Math Grade 5 Module 5 Lesson 6 Homework Answer Key 6

V= area x height

Given, height = 25 cm and area = 45 sq. cm.

V = 45 x 25

V = 1,125 cubic cm.

Given, depth = 12 cm

So, 45 x 12 = 540 cubic cm.

Now, 1125 – 540 = 585

Therefore, 585 millilitre of water is needed to fill the tank

Question 5. Three rectangular prisms have a combined volume of 518 cubic feet. Prism A has one-third the volume of Prism B, and Prisms B and C have equal volume. What is the volume of each prism? Answer:

The total volume of three prisms = 518 cubic feet.

Also given Prism A has one-third the volume of prism B

Now,  518 / 7 = 74 cubic feet

74 x 3 = 222 cubic feet

Therefore, the volume of prism A =74 cubic feet

Volume of prism B and C = 222 cubic feet

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IMAGES

  1. Engage NY // Eureka Math Grade 5 Module 5 Lesson 6 Homework

    lesson 7 homework module 6 grade 5

  2. Math Homework Book Grade 5

    lesson 7 homework module 6 grade 5

  3. Eureka Math Lesson 13 Homework 5.1 Answer Key

    lesson 7 homework module 6 grade 5

  4. Lesson 7 Homework Practice The Real Number System

    lesson 7 homework module 6 grade 5

  5. Eureka Math Grade 5 Lesson 6 Homework 5 2 Answer Key

    lesson 7 homework module 6 grade 5

  6. Grade 6 Module 6 Lesson 5

    lesson 7 homework module 6 grade 5

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  1. lesson 25 homework module 7 grade 2

  2. Eureka math grade 5 module 6 lesson 6 homework

  3. lesson 15 homework module 7 grade 2

  4. MODULE 5 in TLE-6

  5. lesson 5 homework module 7 grade 3

  6. lesson 6 homework module 6 grade 3

COMMENTS

  1. Eureka Math Grade 5 Module 6 Lesson 7 Answer Key

    6. 7. (6, 7) a. Points are plotted and all points are connected with a straight line . b. A rule showing the relationship between the x- and y-coordinates of points on the line is the difference between x and y coordinates of all points is 1 . The x-coordinate and y-coordinate both are increased by 2 with respective to the x and y coordinates .

  2. Eureka math grade 5 module 6 lesson 7 homework

    Plot points, use them to draw lines in the plane, describe patterns, within coordinate pairs, help students, help teachers, help parents, graphing, x and y r...

  3. PDF Grade 5 • MODULE 6

    Lesson 5 Homework 5•6 Lesson 5: Investigate patterns in vertical and horizontal lines, and interpret points on the plane as distances from the axes. 5. Write the coordinate pairs of 3 points that can be connected to construct a line that is 5 1 2 units to the right of and parallel to the U-axis. a. _____ b.

  4. Engage NY // Eureka Math Grade 5 Module 6 Lesson 7 Homework

    Engage NY // Eureka Math Grade 5 Module 6 Lesson 7 Homework @TheHomeworkHelper.

  5. 5th Grade Math (Eureka Math/EngageNY)

    Unit 5: Module 5: Addition and multiplication with volume and area. 0/1400 Mastery points. Topic A: Concepts of volume Topic B: Volume and the operations of multiplication and addition Topic C: Area of rectangular figures with fractional side lengths. Topic D: Drawing, analysis, and classification of two-dimensional shapes.

  6. Eureka Math Grade 5 Module 6 Lesson 7

    EngageNY/Eureka Math Grade 5 Module 6 Lesson 7For more videos, please visit http://bit.ly/eurekapusdPLEASE leave a message if a video has a technical difficu...

  7. Eureka Math Grade 7 Module 6 Lesson 5 Answer Key

    Eureka Math Grade 7 Module 6 Lesson 5 Problem Set Answer Key. Given the following triangle correspondences, use double arrows to show the correspondence between vertices, angles, and sides. Question 1. Question 2. Question 3. Name the angle pairs and side pairs to find a triangle correspondence that matches sides of equal length and angles of ...

  8. Eureka Math Grade 5 Module 5 Lesson 7 Answer Key

    V = 6 x 5 x 12. V = 360 cubic metres. According to given condition of doubling the volume, then. Volume = 2880 cubic metres. 288 cubic metres is much larger than 360 cubic metres. So, volume will not be double. Eureka Math Grade 5 Module 5 Lesson 7 Homework Answer Key. Wren makes some rectangular display boxes. Question 1.

  9. PDF Teacher Edition Eureka Math Grade 7 Module 5

    Grade 7 Module 5 Teacher Edition FL State Adoption Bid # 3691. ISBN 978-1-64054-359-1 Printed in the U.S.A. This book may be purchased from the publisher at eureka-math.org. ... Lesson 5: Chance Experiments with Outcomes That Are Not Equally Likely ..... 53 Lesson 6: Using Tree Diagrams to Represent a Sample Space and to Calculate Probabilities ...

  10. Course: G5M5: Addition and Multiplication with Volume and Area

    Grade 5 Module 5 Collapse all Expand ... Homework Solutions Page. Promethean Flipchart Page. Google Slides Page. Exit Ticket Solutions Page. ... Lesson 4. Lesson 5. Lesson 6. Lesson 7. Lesson 8. Lesson 9. Mid-Module Review. Topic C: Area of Rectangular Figures with Fraction... Lesson 10. Lesson 11. Lesson 12. Lesson 13.

  11. Printed Materials

    As the creator of Engage NY Math and Eureka Math, Great Minds is the only place where you can get print editions of the PK-12 curriculum.Our printed materials are available in two configurations: Learn, Practice, Succeed, or student workbooks, teacher editions, assessment and fluency materials. The Learn, Practice, Succeed configuration is available for grades K-8 and offers teachers ...

  12. Course: G5M6: Problem Solving with the Coordinate Plane

    Problem Solving with the Coordinate Plane. Eureka Essentials: Grade 5. An outline of learning goals, key ideas, pacing suggestions, and more! Fluency Games. Downloadable Resources. Teacher editions, student materials, application problems, sprints, etc. Application Problems.

  13. EMBARC: All courses

    Courses. Grade 5. Eureka Math and EngageNY resource for 5th grade. Grade 5 General Resources. A 5th grade resource for teachers using Eureka Math and EngageNY. G5M1: Place Value and Decimal Fractions. A 5th grade resource for teachers using Eureka Math and EngageNY. G5M2: Multi-Digit Whole Number and Decimal Fraction Operations.

  14. Common Core Grade 5 Math (Worksheets, Homework, Lesson Plans)

    Grade 5 Homework, Lesson Plans And Worksheets. Module 1 Topics and Objectives; ... Standard: 5.NBT.6, 5.NBT.7 Days: 2 Topic H Overview Lesson 28, ... Standard: 5.G.1 Days: 6 Module 6 Overview Topic A Overview Lesson 1: Construct a coordinate system on a line. (Video Lesson)

  15. Homework Helpers / Home

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  16. Eureka math grade 5 module 5 lesson 6 homework

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  17. PDF Teacher Edition Eureka Math Grade 7 Module 6

    A STORY OF RATIOS D } µ o K À À ] Á ó {6 Module 6: Geometry Grade 7 {Module 6 Geometry Ks Zs/ t In Module 6, students delve further into several geometry topics they have been developing over the years. Grade 7 presents some of these topics (e.g., angles, area, surface area, and volume) in the most challenging

  18. Eureka Math Grade 6 Module 5 Lesson 7 Answer Key

    Eureka Math Grade 6 Module 5 Lesson 7 Example Answer Key. Question 1. Determine the lengths of the given line segments by determining the distance between the two endpoints. Answer: Eureka Math Grade 6 Module 5 Lesson 7 Exercise Answer Key. Question 1. complete the table using the diagram on the coordinate plane. Answer:

  19. Eureka math grade 5 module 5 lesson 6 problem set

    Find the total volume of solid figures composed of two non-overlapping rectangular prisms

  20. Eureka Math Grade 5 Module 6 Lesson 5 Answer Key

    Eureka Math Grade 5 Module 6 Lesson 5 Homework Answer Key. Question 1. Use the coordinate plane to answer the questions. a. Use a straightedge to construct a line that goes through points A and B. Label the line g. b. Line g is parallel to the ______-axis and is perpendicular to the ______-axis. c. Draw two more points on line g.

  21. PDF Grade 6, Module 5 Student File A

    10 9 8 7 6 5 4 3 2 1 Eureka Math™ Grade 6, Module 5 Student File_A Contains copy-ready classwork and homework A Story ... Lesson 2 6•5 Lesson 2 : S.7The Area of Right Triangles 5. 6. Mr. Jones told his students they each need half of a piece of paper. Calvin cut his piece of paper horizontally, and

  22. Engage NY // Eureka Math Grade 6 Module 5 Lesson 7 Problem Set

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  23. Eureka Math Grade 5 Module 5 Lesson 6 Answer Key

    Engage NY Eureka Math 5th Grade Module 5 Lesson 6 Answer Key Eureka Math Grade 5 Module 5 Lesson 6 Problem Set Answer Key. Question 1. Find the total volume of the figures, and record your solution strategy. a. Volume: _____ Solution Strategy: Answer: Volume = length x width x height. V= 14 x 10 x 3. V = 420 cubic centimetres. Solution strategy :